Reverend Thomas Bayes vs. 9/11 Conspiracies

The 9/11 Truth movement has come up a few times lately, so I thought I'd take the time to sketch out my reasoning for being so skeptical, as well as so apathetic about the evidence.

I cannot properly do this without using Bayes' theorem, so I need to explain that first. (Bayes' theorem is very useful, and I would recommend learning it even if you don't care about 9/11 conspiracies.)

In plain English, the theorem says you should take prior probabilities into account when judging how likely something is. Symbolically, it can be formulated like this:

[ P(H) / P(~H) ] × [ P(D|H) / P(D|~H) ] = P(H|D) / P(~H|D)

This looks like a mess, but it's fairly simple once you know what the symbols mean.

I'm using "H" to stand for "hypothesis", and "D" for "data". P(H) is the probability that the hypothesis is true, to the best of our knowledge, before we examine the data. "~" means "not", so P(~H) is the probability that it is not true, as far as we can make out, before we look at the data.

This means the first third of the equation,

[ P(H) / P(~H) ]

is the prior odds (not the probability, but the odds now) of the hypothesis being true. If we think, before looking at the data, that the odds are 50/50, then this part of the equation is 50/50 (or, after simplifying, just 1).

P(H|D) is the probability that the hypothesis is true, after taking into account the new data. P(~H|D) is, likewise, the probability that it is not true after accounting for the new data. Thus, the right side of the equation,

P(H|D) / P(~H|D)

is the posterior odds, the odds of the hypothesis being true after seeing the new data.

Lastly, in the middle, we have

[ P(D|H) / P(D|~H) ]

P(D|H) is the probability that we would see the data we have if our hypothesis is true. P(D|~H) is the probability of seeing the same data if the hypothesis is false. Combined in this middle term, they are called the likelihood ratio.

We can now make the equation more manageable by substituting English:

prior odds × likelihood ratio = posterior odds

Let me use an example. Let's suppose you went to a doctor, suspecting you had a certain disease. We'll say the hypothesis, H, is that you have the disease. According to studies, only 1 in 10,001 people have this disease. So the prior odds that you have it are 1/10,000.

The doctor then takes a blood sample and runs a test. The test is 99% accurate, making the likelihood ratio 99. It comes back positive.

This is really terrible news. Or is it?

If we do the math to find out the odds that you have the disease, taking all the data into account — solving for the posterior odds — we get 99 to 10,000, or slightly less than a 1 in 100 chance that you have the disease.

How did that happen? Basically, because the disease is so rare, you're 100 times more likely to be a healthy person who receives a false positive than to be someone who actually has the disease.

On to the point. When I think about 9/11 conspiracies, I think about them in Bayesian terms. This time let H be the hypothesis that George Bush orchestrated 9/11. What's the likelihood — ignoring the evidence collected after the fall of the twin towers — that president Bush could have coordinated all of this? Given the complexity of the operation, it would have been very difficult. Not to mention that there must have been dozens, if not hundreds, of top officials involved in this, all of whom had a good chance of being treated like heroes if they prevented it. How did he keep them from talking? How did he keep other people from noticing? The whole idea strains credulity. How about the angry Muslims hypothesis? After 50 years of malevolent U.S. intervention in the Middle East, it sounds pretty plausible. Even more so after the U.S.S. Cole incident. Because of the extreme imbalance between the two options, I'm giving the prior odds the value of 1/500.

What about the evidence collected after the disaster? I guess it's plausible it could have been caused by explosives. It's also plausible (to me) that 9/11 conspiracy theorists are not very good at forensics, and simply read too much into the evidence. So I'll give the likelihood ratio a value of 1/1, or just 1. Wow, that's a little unsettling, a 50/50 chance that the evidence was caused by explosives! Well, no, not really. If you do the math,

(1/500) × 1 = 1/500

you find that it's still extremely unlikely that George Bush caused 9/11.

Now, I get the impression that many 9/11 Truthers, like the patient who panicked earlier after getting positive results on his blood test, are looking at their data out of context, ignoring the extreme unlikelihood of their hypothesis in the first place.

Just for fun, let's take this a little further. Even if I give assumptions that are far too kind, it's still unlikely:

(1/50) × 10 = 1/5

In fact, given my value of 1/500 for the prior odds, if I wanted merely 50/50 posterior odds that George Bush was responsible, the evidence collected after 9/11 would have to suggest a likelihood ratio of 500 to 1 that explosives, not planes, destroyed the buildings. In order to get this number, we would basically have to find the detonator intact with George Bush's fingerprints on them. And then get confessions from a dozen senior officials. And then find written instructions for the destruction of the twin towers in a drawer of the desk in the Oval Office. It's pretty silly.

And that's why I don't bother with this issue.

Who Are The Real Democrats?

Here's a letter I recently wrote to the Sentinel:


Who's a "real" Democrat?

There have a number of letters in the last month about libertarian Democrats, and how voters should “beware” of these candidates.

I am both amused and frustrated by these arguments.

The authors don’t seem to understand what the word “libertarian” actually means. Libertarians, for their information, want minimal government involvement in society. This means they generally oppose government intervention in the economy. They also oppose intervention in citizens’ private lives, as well as foreign wars of aggression.

If you’ll notice, this means that, though there may be times when they agree with conservatives, there are a considerable number of issues where libertarians naturally align with the left, including marijuana, gay rights, immigration, foreign policy, civil liberties, corporate welfare, and others. In fact, there are prominent libertarians, notably Will Wilkinson, arguing that libertarians should form a permanent alliance with liberals. This alliance has been branded “liberaltarianism,” and that’s exactly what some of us in Cheshire County have set out to do.

You would expect Democrats to be enthused by this influx of support. And, indeed, most have responded this way. Unfortunately, there are some who, due to narrow-minded ignorance and rampant fear-mongering, have decided that it’s their duty to oppose libertarianism in the Democratic Party. Apparently libertarians aren’t “real” Democrats.

Is that so? Well, let’s take a look at a few of these “real” Democrats. “Real” Democrat John Lynch vetoed medical marijuana and has pledged to oppose an income tax. (“Stealth” Democrat Andrew Carroll, on the other hand, supports medical marijuana and has refused to take the income tax pledge.) “Real” Democrat Bill Butynski opposes gay marriage and medical marijuana, and has been endorsed by Rep. Tim Butterworth. (“Stealth” Democrat Thom Simmons, however, supports gay marriage and medical marijuana, and has been endorsed by the Pink Pistols, a gay rights organization.)

If there is any systematic reasoning at all behind this categorization, I cannot see it.

I have therefore decided that I am not supporting real Democrats this year. Instead, I will support thoughtful and intelligent candidates who will vote with their consciences — candidates like Chuck Weed, Stephen Lindsey, Kris Roberts, Tim Robertson, Andrew Carroll and Thom Simmons.

WILL MAY
45 Elm St.
Keene